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This is a discussion on INTP and INTJ females unite! within the NT's Temperament Forum- The Intellects forums, part of the Keirsey Temperament Forums category; Originally Posted by FlaviaGemina OK, girls, here's another random question. Out of the following, who do you get along best ...
I suck at typing people IRL. I think my best friend is INTP female. We've been friends for over 25 years. Some of her personality traits are annoying (way too much detail!) but the in-depth discussions we have had are absorbing and beautifully random. My daughter is an INTJ and I adore her. There's an instinctive, sublingual understanding between us that goes beyond the parent-child connection -- so much deeper than what I have with my parents. Another close friend is INTJ female and the connection is the same as with my daughter, although not as strong. I had a brief fling with an INTJ male and, again, felt that connection. He commented that he'd never experienced the ease of conversation that we had. He said it as if he had never expected a woman to keep up with intellectually. I don't think I've met an INTP male IRL.
Online, I've enjoyed conversations with all four types. The only times I've felt dissonance are with individuals who are trying to fit into a stereotype that is clearly not close enough to their natural personalities to be comfortable. I'd say that's the case regardless of type.
I'm pretty terrible at typing people. I suspect one of my male friends is an INTJ and we get along well but I don't know if I know any of the other INTP/J types so can't say how I'd get along with the others.
I have gotten along better with INTP boys and girls but not other INTJ's. I'm not sure if it was because of the actual person they were. It's not like they were a mirror to me but I've just found INTP's hunger for theories and occasional spontaneity both fascinating and invigorating. I'm sure some INTJ's are or could be the same as well but not the ones I have met. Both have a tendency towards thinking that they are right and you are wrong or they are right and you are lesser unless you come up with an idea that is ingenious within 30 seconds. I'm trying to do that less...I think I'm getting better at it but I think it'll always be a problem with me...so I need to keep it in check :o). Listening to the entire sentence before jumping to a conclusion helps. It helps us learn more and shut off less I think.
@RedX, or anyone who's good at maths.
I need help. I'm pre-learning some maths for next school year to help my pupil.
Today I did about proofs.
Here's one of the questions and my answer. Can you tell me whether I did it right? The book doesn't give the answers for this chapter.
"Prove by direct argument that the sum of the squares of any 5 consecutive integers is divisible by 5".
my answer:
m2 + (m+1)2 + (m+2)2 + (m+3)2 +(m+4)2 = x
m2 + ( m2+2m + 1) + ( m2+4m + 4) + ( m2+6m + 9) + ( m2+8m + 16) = x
5m2 + 20m + 30 = x
m2 + 4m + 6 = x/5
Then I put some random numbers for m to test it
e.g. m = 2
5*22 + 20*2 +30 = 20 + 40 + 30 = 90
22 + 4*2 + 6 = 4 + 8 + 6 = 18
90/5 = 18
Is this right? The book didn't really explain what "by direct argument" means. Some of the examples of it look more like "by exhaustion".
THANKS
Someone sent me here to look at this post ... but I am gender neutral, so I hope it is okay
(... I'm also an NF... I iz in your bases, NTs (Please don't hurt me))
It looks like you did it right, but I'm going to redo it just to check the arithmetic
m2 + (m+1)2 + (m+2)2 + (m+3)2 +(m+4)2 = q5 + r .... = r (mod 5) ... note: by the division algorithm q and r are unique (0<=r<5)
m2 + (m+1)2 + (m+2)2 + (m+3)2 +(m+4)2 = m2 + ( m2+2m + 1) + ( m2+4m + 4) + ( m2+6m + 9) + ( m2+8m + 16)
= 5m2 + 20m + 30 = (m2 + 4m + 6)5 = q*5 + r
r=0, q=m2 + 4m + 6 ... since m is an integer, q is an integer
i.e. There exists an integer q such that m2 + (m+1)2 + (m+2)2 + (m+3)2 +(m+4)2 = q*5
Yup ... you did it correctly ... directly just means that you start with the premise (The addition on 5 consecutive numbers is equal to an integer, c) and work your way to the conclusion (c is divisible by 5)
Another common proof technique is a subset of indirect proofs:
Assume c is not divisible by 5 ... now prove that assumption leads to a contradiction
Thank you ^__^ *hug*
By additions did you mean the division algorithm and/or modulo a number (mod 5)?
They are just other ways to look at whether or not a divides b
Divisor - Wikipedia, the free encyclopedia
Division Algorithm (link from wikipedia that can be used for two negative numbers too)
Euclidean division - Wikipedia, the free encyclopedia
Modulo:
Modular arithmetic - Wikipedia, the free encyclopedia
You don't need to write it down, but some people might be able to picture it easier by looking at the problem through the lens of these mathematical ideas ^__^
@Mr. Meepers , thanks. I don't think my kid will have to answer these questions to such a high level. (Or at least I hope he won't, because if I have to help him with it, that will create more work for me :) ) It's 'only' A-level (Year 13 at high school).
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